# Is it possible to factor #y=x^3 - 2x^2 + 3x -6 #? If so, what are the factors?

##### 1 Answer

May 28, 2016

#### Explanation:

Group the terms in 'pairs' thus

#[x^3-2x^2]+[3x-6]# now factorise each 'pair'

#x^2(x-2)+3(x-2)# A common factor of (x -2) can now be removed

#rArr(x-2)(x^2+3)#